1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# Match the entries of column I with the entries of column II in the following table. Column I Column II (A) Magnetic field due to infinite long wire (P) B=μ0I2πd (B) Magnetic field due to current element (Q) B=μ0IN2R (C) Magnetic field at centre of current carrying coil (R) B=μ0INR22(x2+R2)3/2 (D) Magnetic field at axis of coil (S) dB=μ04πIdlsinθr2 Which of the following option has the correct combination, considering column I and column II?

A
AP
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
BQ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
CR
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
DS
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is A A→PWe know that, magnetic field due to - (1) Infinite long wire : B=μ0I2πd ∴A→P (2) Current element : dB=μ04πIdlsinθr2 ∴B→S (3) Current carrying coil at its centre : B=μ0IN2R ∴C→Q (4) Current carrying coil at its axis : B=μ0INR22(x2+R2)3/2 ∴D→R Hence, option (A) is correct.

Suggest Corrections
1
Join BYJU'S Learning Program
Related Videos
Magnetic Field Due to a Current Carrying Wire
PHYSICS
Watch in App
Join BYJU'S Learning Program