The correct option is
D A - 2, B - 3, C - 5, D - 4
1 mole of a gas at STP corresponds to 22.4 L.
3 g of ethane corresponds to
330=0.1 mole.
Therefore, it occupies 2.24 L volume at STP.
7 g nitrogen gas corresponds to 728=0.25 mole.
Thus, it occupies 5.6 L at STP.
3.55 g chlorine gas corresponds to 3.5571=0.05 mole.
Thus, they occupy 1.12 L at STP.
8.8 g carbon dioxide corresponds to 8.844=0.2 mole. Thus, they occupy 4.48 L at STP.
Hence, option C is correct.