Question

Match the following.
$\begin{array}{cc}\text{Reaction}& \text{Degree of dissociation in terms of}\\ \text{(Homogeneous gaseous phase)}& \text{equilibrium constant}\\ \text{(a)}A\left(g\right)+B\left(g\right)\rightleftharpoons 2C\left(g\right)& \text{(p)}\left(\sqrt{K}\right)/(1+\sqrt{K})\\ \text{(b)}2A\left(g\right)\rightleftharpoons B\left(g\right)+C\left(g\right)& \text{(q)}\left(\sqrt{K}\right)/(2+\sqrt{K})\\ \text{(c)}A\left(g\right)+B\left(g\right)\rightleftharpoons C\left(g\right)+D\left(g\right)& \text{(r)}2K/(1+2K)\\ \text{(d)}AB\left(g\right)\rightleftharpoons \frac{A}{2}\left(g\right)+\frac{B}{2}\left(g\right)& \text{(s)}\frac{2\sqrt{K}}{1+2\sqrt{K}}\\ & \text{(t) K}\end{array}$

• A. $\text{a}–\text{q},\text{b}–\text{s},\text{c}-\text{p},\text{d}-\text{r}$
• B. $\text{a}–\text{q},\text{b}–\text{p},\text{c}-\text{s},\text{d}-\text{r}$
• C. $\text{a}–\text{r},\text{b}–\text{s},\text{c}-\text{p},\text{d}-\text{q}$
• D. $\text{a}–\text{s},\text{b}–\text{p},\text{c}-\text{r},\text{d}-\text{q}$

Answer 1

The correct option is A $\text{a}–\text{q},\text{b}–\text{s},\text{c}-\text{p},\text{d}-\text{r}$

a) $A\left(g\right)+B\left(g\right)\rightleftharpoons 2C\left(g\right)$
$K=\frac{4c^2{\alpha }^2}{c^2(1-\alpha {)}^2}$

$\alpha =\frac{\sqrt{K}}{2+\sqrt{K}}$

b) $2A\left(g\right)+B\left(g\right)\rightleftharpoons C\left(g\right)$
$K=\frac{\frac{c^2{\alpha }^2}{4}}{c^2(1-\alpha {)}^2}$

$\alpha =\frac{2\sqrt{K}}{1+2\sqrt{K}}$

c) $A\left(g\right)+B\left(g\right)\rightleftharpoons C\left(g\right)+D\left(g\right)$
$K=\frac{c^2{\alpha }^2}{c^2(1-\alpha {)}^2}$

$\alpha =\frac{\sqrt{K}}{1+\sqrt{K}}$

d) $AB\left(s\right)\rightleftharpoons \frac{A\left(g\right)}{2}+\frac{B\left(g\right)}{2}$
$K=\frac{\frac{c^2{\alpha }^2}{4}}{c-c\alpha }$

$\alpha =\frac{2K}{1+2K}$