Match the following equations with corresponding conic:
We have to decide the curve represented by the equations given. The systematic way of finding the conic is as follows.
Let the equation of the curve be
ax2+2hxy+by2+2gx+2fy+c=0 and
△=abc+2fgh−af2−bg2−ch2
1) Find △
2) If △=0, it represents a pair of straight lines.
3) If △≠0, it is a conic.
To decide the type of conic, we will compare h2 and ab.
4) If h2=ab⇒ parabola.
5) If h2<ab⇒ ellipse or circle.
For circle, a=b and h=0
6) If h2>ab⇒ hyperbola.
We will go through each equation and decide the conic it represents.
(I) x2−2x−y=0
a=1, b=0, h=0, g=−1, f=−12
△=0+0−1×(−12)2−0−0=−14≠0
⇒ It is the equation of a conic.
Now, h2=0 and ab=0
∵h2=ab⇒ It is a parabola.
(II) x2+y2−20=0
If a=b and h=0, it represents a circle.
Here, a=b=1 and h=0 ⇒ It is a circle.
(III) Clearly, x+2y+3=0 is a linear equation which is the equation of a straight line.