Now,
for x+2y=1...(1) and x+y=1...(2)
equation (1) - (2)
⇒y = 0
Putting y = 0 in equation (1)
We get, x = 1
for x+3y=4...(1) and x-3y=2...(2)
equation (1) + (2)
⇒x = 3
Putting x = 3 in equation (1)
We get, y = 13
for 2x+4y=4..(1) and 2x+y=1...(2)
equation (1) - (2)
⇒y = 1
Putting y = 1 in equation (1)
We get, x = 0