Question

Match the following figures:

Answer 1

$$\begin{gathered} \text{(a)} \\ \text{The given figure is a cuboid with sides 4, 4 and 6 units.} \\ \text{Area of a rectangle =length×width} \\ \therefore \text{Area of the rectangular face sith sides 4 and 4 =4×4=16} \\ \text{And, area of the other face with sides 4 and 6 =4×6=24} \\ \text{Thus, the net for the given figure will have four faces with area 24 and two faces with area 16.} \\ \text{Observe net (iv) satisfies this.} \\ \text{Thus, the net of figure (a) is net (iv).} \end{gathered}$$



$$\begin{gathered} \text{(b)} \\ \text{The given figure is a cuboid with sides 3, 3 and 8.} \\ \text{Area of a}\mathrm{rectangle}\text{=length×width} \\ \text{∴ Area of the rectangular face sith sides 3 and 3 =3×3=9} \\ \text{And the area of the other face with sides 3 and 8 =3×8=24} \\ \text{Thus, the net for given figure will have four faces with area 24 and two faces with area 9.} \\ \text{Observe that net (i) satisfies this.} \\ \text{Thus, the net of figure (b) is net (i).} \end{gathered}$$



$$\begin{gathered} \text{(c)} \\ \text{The given figure is a cuboid with sides 3, 4 and 6.} \\ \text{Area of a}\mathrm{rectangle}\text{=length×width} \\ \therefore \mathrm{A}\text{rea of the rectangular face sith sides 3 and 4 =3×4=12,} \\ \mathrm{A}\text{rea of the rectangular face with sides 4 and 6 =4×6=24} \\ A\text{nd, area of the other face with sides 3 and 6 =3×6=18} \\ \text{Thus, the net for given figure will have two faces with area 24, two faces with area 18 and two faces with area 12.} \\ \text{Observe that net (ii) satisfies this.} \\ \text{Thus, the net of figure (c) is net (ii).} \end{gathered}$$



$$\begin{gathered} \text{(d)} \\ \text{The given figure is a cuboid with sides 3, 3 and 9.} \\ \text{Area of a}\mathrm{rectangle}\text{=length×width} \\ \text{Area of the rectangular face with sides 3 and 3 =3×3=9,} \\ \mathrm{A}\text{nd, area of the other face with sides 3 and 9 =3×9=27} \\ \text{Thus, the net for given figure will have four faces with area 27 and two faces with area 9.} \\ \text{Observe that net (iii) satisfies this.} \\ \text{Thus, the net of figure (d) is net (iii).} \end{gathered}$$