Match the following:
Given sinx = (25) and x∈(0,π2)
(p) cosx(1)52(q) tanx(2)√212(r) cscx(3)√215(4)2√21None of these
As x is an acute angle,
We will construct the triangle in such a way that sinx = 25 (Above figure).
Using Pythagoras theorem, we can find the 3rd side of the △.
So the triangle will be
Now, cosx = √215 (AdjacentHypotenuse)
tanx = 2√21 (OppositeAdjacent)
cscx = 52 (HypotenuseOppositeor1sinx)
So the answer is p−3,q−4,r−1