The correct option is
We know that (x+y)2=x2+y2+2xy
So, (a+2)2=a2+22+2×a×2
=a2+4+4a
We know that (x−y)2=x2+y2−2xy
So, (a−1)2=a2+12−2×a×1
=a2+1−2a
We know that (x+y)(x−y)=x2−y2
So, (a+3)(a−3)=a2−32=a2−9
Similarly, (a+1)2+(a−1)2
=a2+1+2a+a2+1−2a
=2a2+2=2(a2+1)