Question

Match the following:

List-I	List-II
1. Area bounded by $y=|x|$ and $y=2$ is	a. 4
2. Area bounded by $\frac{|x|}{a}+\frac{|y|}{b}=1$, when $a,b>0$ is	b. $\frac{(\pi -2)ab}{4}$
3. Area between the ellipse $\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$ and the chord $\frac{x}{a}+\frac{y}{b}=1$	c. 1
4. Area bounded by $y=\left[x\right]$, the $x$-axis and $x=1,x=2$ is	d. 2ab

The correct match is

• A. $1-a,2-d,3-c,4-b$
• B. $1-a,2-d,3-b,4-c$
• C. $1-b,2-d,3-a,4-c$
• D. $1-a,2-b,3-c,4-d$

Answer 1

The correct option is B $1-a,2-d,3-b,4-c$

1. $y=|x|$ and $y=2$
$Area=\frac{1}{2}\times \left(4\right)\left(2\right)$
$=4squnits.$
2. $\frac{1}{2}ab\times 4=2absqunits$
3. $\frac{1}{4}\pi ab-\frac{2ab}{4}=\frac{(\pi -2)ab}{4}squnits.$
4. $\stackrel{2}{\underset{1}{\int }}dx=1squnits.$
Hence, option 'B' is correct.