Match the hydrocarbons in Column I with the boiling points given in Column II- Column I Column II- A n-Pentane i 282-5 K- B iso-Pentane ii 309 K- C neo-Pentane iii 301 K- -

Correct answer: (A)→ ii, (B) → iii, (C)→ i. Boiling point ∝ Molecular mass Boiling point ∝1Branching Thus, as molecular mass increases, boiling point increa ...

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Standard IX

Chemistry

Polyatomic Molecules

Match the hyd...

Question

Match the hydrocarbons in Column I with the boiling points given in Column II.

$\begin{matrix} Column I & Column II (A) & n-Pentane & (i) & 282.5 K (B) & iso-Pentane & (i i) & 309 K (C) & neo-Pentane & (i i i) & 301 K \end{matrix}$

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Solution

Correct answer:

$(A) \to i i, (B) \to i i i, (C) \to i .$

Boiling point $\propto$ Molecular mass

Boiling point $\propto \frac{1}{Branching}$

Thus, as molecular mass increases, boiling point increases

For the given compounds: n-Pentane, iso-Pentane, neo-Pentane molecular mass is same but order of branching is:

Order of branching in given compounds:

Therefore, boiling point order is:

n-Pentane > iso-Pentane > neo-Pentane

Thus
$(A) \to i i : n-Pentane 309K$
$(B) \to i i i : Iso-Pentane 301K$
$(C) \to i : n e o - P e n t a n e 282.5 K$

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Match the hydrocarbons in Column I with the boiling points given in Column II. Column IColumn II(A)n-Pentane(i)282.5 K(B)iso-Pentane(ii)309 K(C)neo-Pentane(iii)301 K

Match the hydrocarbons in Column I with the boiling points given in Column II.

$\begin{matrix} Column I & Column II (A) & n-Pentane & (i) & 282.5 K (B) & iso-Pentane & (i i) & 309 K (C) & neo-Pentane & (i i i) & 301 K \end{matrix}$