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Byju's Answer
Standard XII
Chemistry
Electronic Configuration and Oxidation States
Match the Lis...
Question
Match the List-I with List-II and select the correct answer from the given Codes.
List-I
List-II
(Compound)
(Oxidation state of nitrogen)
N
2
O
5
−
2
N
a
N
3
+
5
NO
−
1
/
3
N
2
H
4
+
2
A
A-(ii), B(iii), C-(iv), D-(i)
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B
A-(i), B-(ii), C-(iii), D-(iv)
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C
A-(iv), B-(i), C-(ii), D-(iii)
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D
A-(iii), B-(i), C-(iv), D-(ii)
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Solution
The correct option is
A
A-(ii), B(iii), C-(iv), D-(i)
1.
N
2
O
5
Oxidation state of oxygen=-2
So oxidation state of nitrogen=+5
2.
N
a
N
3
Oxidation state of sodium=+1
So oxidation state of nitrogen=-1/3
3.
N
O
Oxidation state of oxygen=-2
So oxidation state of nitrogen=+2
4.
N
2
H
4
Oxidation state of hydrogen=+1
So oxidation state of nitrogen=-2
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