Question

Match the reactions given in Column I with the suitable reagents given in Column II.
$\begin{array}{cccc}& \text{Column I(Reactions)}& & \text{Column II(Reagents)}\\ \text{A}& \text{Benzophenone}\to \text{Diphenylmethane}& \left(i\right)& \text{LiAlH\_4}\\ \text{B}& \text{Benzaldehyde}\to \text{1-Phenylethanol}& \left(ii\right)& \text{DIBAL−H}\\ \text{C}& \text{Cyclohexanone}\to \text{Cyclohexanol}& \left(iii\right)& \text{Zn(Hg)/ conc. HCl}\\ \text{D}& \text{Phenyl benzoate}\to \text{Benzaldehyde}& \left(iv\right)& \text{CH\_3MgBr}\end{array}$

Answer 1

Part (A)

The benzophenone is reduced to diphenylmethane in the presence of$Zn-Hg/$ conc.$HCl$. The reaction is known as clemmensen reduction.


$\begin{array}{cccc}\text{A}& \text{Benzophenone}\to \text{Diphenylmethane}& \left(iii\right)& \text{Zn(Hg)/ conc. HCl}\end{array}$


Part (B)
The benzaldehyde is reduced to phenyl ethanol in the presence of $C{H}_{3}MgBr$followed by hydrolysis.


$\begin{array}{cccc}\text{B}& \text{Benzaldehyde}\to \text{1-Phenylethanol}& \left(iv\right)& \text{CH\_3MgBr}\end{array}$

Part (C)
The cyclohexanone is reduced to cyclohexanol in the presence of $LiAl{H}_4$.


$\begin{array}{cccc}\text{C}& \text{Cyclohexanone}\to \text{Cyclohexanol}& \left(i\right)& \text{LiAlH\_4}\end{array}$

Part (D)
The phenyl benzoate is reduced to benzaldehyde in the presence of $DiBAL-H.$


$\begin{array}{cccc}\text{D}& \text{Phenyl benzoate}\to \text{Benzaldehyde}& \left(ii\right)& \text{DIBAL−H}\end{array}$

Correct match

$\begin{array}{cccc}& \text{Column I(Reactions)}& & \text{Column II(Reagents)}\\ \text{A}& \text{Benzophenone}\to \text{Diphenylmethane}& \left(iii\right)& \text{Zn(Hg)/ conc. HCl}\\ \text{B}& \text{Benzaldehyde}\to \text{1-Phenylethanol}& \left(iv\right)& \text{CH\_3MgBr}\\ \text{C}& \text{Cyclohexanone}\to \text{Cyclohexanol}& \left(i\right)& \text{LiAlH\_4}\\ \text{D}& \text{Phenyl benzoate}\to \text{Benzaldehyde}& \left(ii\right)& \text{DIBAL−H}\end{array}$