Question

Match the reciprocal of each of the following in exponential form.

$\left(1\right)$	$3^2$	$\left(a\right)$	${(-\frac{7}{3})}^{89}$
$\left(2\right)$	$(-5{)}^3$	$\left(b\right)$	${(-\frac{1}{5})}^3$
$\left(3\right)$	${\left(\frac{2}{5}\right)}^4$	$\left(c\right)$	${\left(\frac{1}{3}\right)}^2$
$\left(4\right)$	${\left(\frac{-3}{7}\right)}^{89}$	$\left(d\right)$	${\left(\frac{5}{2}\right)}^4$

• A. $1c,2b,3d,4a$
• B. $1c,2b,3c,4d$
• C. $1b,2c,3d,4a$
• D. $1d,2a,3b,4c$

Answer 1

Answer: (A)

$1c,2b,3d,4a$

Since the powers on both side of the columns are positive, if we have to take a reciprocal, we just have to take inverse of the value inside the brackets,

So,

(1) $3^2$ $=$ $(\frac{1}{3}{)}^2$ $=c$

(2)$(-5{)}^3=(\frac{-1}{5}{)}^3$ $=b$

(3) $(\frac{2}{5}{)}^4=(\frac{5}{2}{)}^4$ $=d$

(4) $(\frac{-3}{7}{)}^{89}=(\frac{-7}{3}{)}^{89}$ $=a$

So, the answer is A