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Question

Match the statements of Column A (Description of atoms forming the molecules) with those of Column B (Forces of attraction among the molecules)


Column 1Column 2

A has 7protons and B has 1 proton.

Interionic attraction

Both the atoms have identical electronic configurations.

Dipole-dipole interaction

A has 20 protons and B has 8 protons.

H— bonding

A has 1 proton and B has 16 protons.

Van der Waals’ forces of attraction

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Solution

Explanation of correct matching

Atomic number - The number of protons of an atom in its ground state.

A-III

  • A is Nitrogen (N;Z=7) and B is Hydrogen (H;Z=1). They will form Ammonia (NH3).
  • Ammonia has intermolecular H-bonding.
  • H3NH-NH2

B-IV

  • Both the atoms have identical electronic configurations means they will form a non-polar homo-diatomic molecule.
  • These kinds of molecules usually have a London force of attraction which is one of Van der Waal's forces of attraction.

C-I

  • A is Calcium (Ca;Z=20) and B is Oxygen (O;Z=8).
  • The compound they form is Calcium oxide (CaO). Calcium oxide is an ionic compound.
  • The cation Ca2+ and anion O2- will have an interionic attraction between them.

D-II

  • A is Hydrogen (H;Z=1) and Sulphur (S;Z=16).
  • The compound they will form is Hydrogen sulphide (H2S).
  • In H2S there is a difference in electronegativity between H and S and because of that the molecule has dipolar nature.
  • Thus, H2S molecules have dipole-dipole interaction between themselves.

Thus, the correct sequence of matching is A-III; B-IV; C-I; D-II.


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