Question

Match the terms mentioned in Column I with the terms in Column II.

	Column I		Column II
A	Carbocation	$\left(i\right)$	Cyclohexane and 1-hexene
B	Nucleophile	$\left(ii\right)$	Conjugation of electrons of $C-H\sigma$ bond with empty p- orbital present at adjacent positively charged carbon.
C	Hyperconjugation	$\left(iii\right)$	$s{p}^2$ hybridized carbon with empty p−orbital
D	Isomers	$\left(iv\right)$	Ethyne
E	$sp$ hybridization	$\left(v\right)$	Species that can receive a pair of electrons
F	Electrophile	$\left(vi\right)$	Species that can supply a pair of electrons

Answer 1

(A) Carbocation :

It is an electron deficient species having $s{p}^2$ hybridised carbon with an empty p-orbital

Hence, the correct match is:
$\left(A\right)\to \left(iii\right)$

(B) Nucleophile :

It is an electron rich species which have negative charge or lone pair of electrons for donation to electrophiles. So, it can supply pairs of electrons.

Hence, the correct match is:

$\left(B\right)\to \left(vi\right)$

(C) Hyper conjugation :

It involves the conjugation of $C-H\sigma$ bond with empty p-orbital present at adjacent positively charged carbon.

Hence, the correct match is:
$\left(C\right)\to \left(ii\right)$

(D) Isomers :

Isomers are molecules of the same formula but having a different arrangement of their atoms. So, given two structures are isomers.



Hence, the correct match is :
$\left(D\right)\to \left(i\right)$

(E) $sp$ hybridisation :

In ethyne molecule, all carbons are sp hybridised

Hence, the correct match is :
$\left(E\right)\to \left(iv\right)$

(F) Electrophile :

It is an electron deficient species. It can receive a pair of electrons from any electron rich species.

Hence, the correct match is :

$\left(F\right)\to \left(v\right)$

So, the correct matches can be represented as:
$\left(A\right)\to \left(iii\right)$ , $\left(B\right)\to \left(vi\right)$ , $\left(C\right)\to \left(ii\right)$ , $\left(D\right)\to \left(i\right)$ , $\left(E\right)\to \left(iv\right)$ , $\left(F\right)\to \left(v\right)$ .