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Byju's Answer
Standard XII
Mathematics
Implicit Differentiation
#8747;sec2 ...
Question
∫
sec
2
x
+
cosec
2
x
d
x
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Solution
∫
sec
2
x
+
cosec
2
x
d
x
=
∫
sec
2
x
d
x
+
∫
cosec
2
x
d
x
=
tan
x
-
cot
x
+
C
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Q.
Prove that
(
i
)
s
e
c
2
θ
+
c
o
s
e
c
2
θ
=
s
e
c
2
θ
c
o
s
e
c
2
θ
(
i
i
)
t
a
n
2
θ
−
s
i
n
2
θ
=
t
a
n
2
θ
s
i
n
2
θ
(
i
i
i
)
t
a
n
2
θ
+
c
o
t
2
θ
+
2
=
s
e
c
2
θ
c
o
s
e
c
2
θ
[3 MARKS]
Q.
s
e
c
2
[
c
o
t
−
1
(
1
2
)
]
+
c
o
s
e
c
2
[
t
a
n
−
1
(
1
3
)
]
=
Q.
∫
s
e
c
2
x
(
s
e
c
x
+
t
a
n
x
)
5
d
x
=
Q.
Question 2
Prove that:
√
s
e
c
2
θ
+
c
o
s
e
c
2
θ
=
t
a
n
θ
+
c
o
t
θ
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