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Byju's Answer
Standard XII
Mathematics
Existence of Limit
limθ→ 0 [ nsi...
Question
lim
θ
→
0
(
[
n
sin
θ
θ
]
+
[
n
tan
θ
θ
]
)
, where [.] represent greatest integer function and
n
∈
N
is equal to
A
2
n
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B
2
n
+
1
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C
2
n
−
1
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D
does not exist
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Solution
The correct option is
A
2
n
[
.
]
gives an integer as a end result we can insert the limit function inside without any change in the final result.
and as we know
lim
x
→
0
s
i
n
θ
θ
=
1
lim
x
→
0
n
t
a
n
θ
θ
=
1
Hence,
[
lim
x
→
0
n
s
i
n
θ
θ
]
=
[
lim
x
→
0
n
t
a
n
θ
θ
]
=
[
n
]
as
n
ϵ
N
,
[
n
]
=
n
Hence,
n
+
n
=
2
n
Suggest Corrections
0
Similar questions
Q.
If
a
=
∑
∞
n
=
1
(
2
n
(
2
n
−
1
)
!
)
and
b
=
∑
∞
n
=
1
(
2
n
(
2
n
+
1
)
!
)
. Find value of [a] + [3b] where [ ] denotes greatest integer function or integral value of x.
Q.
Prove that
1
−
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n
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2
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−
1
)
2
!
−
2
n
(
2
n
−
1
)
(
2
n
−
1
)
3
!
+
.
.
.
+
(
−
1
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n
−
1
2
n
(
n
−
1
)
.
.
.
(
n
+
2
)
(
n
−
1
)
=
(
−
1
)
n
+
1
(
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n
)
2
(
n
!
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2
,
where n is a + ive integer.
Q.
∫
x
0
[
s
i
n
t
]
d
t
where
x
∈
(
2
n
π
,
4
n
+
1
)
π
,
n
∈
N
and
[
.
]
denotes the greatest integer function is equal to .
Q.
lim
x
→
0
−
∑
2
n
+
1
r
=
1
[
x
r
]
+
(
n
+
1
)
1
+
[
x
]
+
|
x
|
+
2
x
(
where
n
ϵ
N
&
[
.
]
denotes the greatest integer function
)
equals
Q.
If
n
is an integer and
(
1
+
i
√
3
)
n
+
(
1
−
i
√
3
)
n
=
2
n
+
1
cos
θ
,
then
θ
is equal to
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