Limx - 0-1 - x2 - -1 - 2xx - x2 is equal to

The correct option is B 12 We have, lim_x → 0√(1 + x^2) √(1 + 2x)x + x^2 This is 00 form, so apply L Hospital rule lim_x → 013(1+x^2)^ 2/ ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Existence of Limit

limx → 0√1 + ...

Question

$lim x \to 0 \frac{\sqrt[3]{1 + x^{2}} - \sqrt[4]{1 + 2 x}}{x + x^{2}}$ is equal to

\frac{1}{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- \frac{1}{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Does not exist

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

{lim}_{x \to 0} \frac{\sqrt[3]{1 + x^{2}} - \sqrt[4]{1 - 2 x}}{x + x^{2}}

f (x) = x^{3} {\sqrt{x^{2} + \sqrt{x^{4} + 1}} - x \sqrt{2}}

l i m x \to \infty f (x)

Evaluate the following one sided limits:

$(i) {lim}_{x \to 2^{+}} \frac{x - 3}{x^{2} - 4}$

$(i i) {lim}_{x \to 2^{-}} \frac{x - 3}{x^{2} - 4}$

$(i i i) {lim}_{x \to 0^{+}} \frac{1}{3 x}$

$(i v) {lim}_{x \to 8^{+}} \frac{2 x}{x + 8}$

$(v) {lim}_{x \to 0^{+}} \frac{2}{x^{\frac{1}{5}}}$

$(v i) {lim}_{x \to \frac{π^{-}}{2}} t a n x$

$(v i i) {lim}_{x \to \frac{π}{2^{+}}} s e c x$

$(v i i i) {lim}_{x \to 0^{-}} \frac{x^{2} - 3 x + 2}{x^{3} - 2 x^{2}}$

$(i x) {lim}_{x \to - 2^{+}} \frac{x^{2} - 1}{2 x + 4}$

$(x) {lim}_{x \to 0^{+}} (2 - c o t x)$

$(x i) {lim}_{x \to 0^{-}} 1 + c o s e c x$

lim x \to 1 [\frac{3}{x^{2} + x - 2} - \frac{4}{x^{2} + 2 x - 3}]

lim x \to 0^{-} \frac{[x] + [x^{2}] + [x^{3}] + . . . + [x^{2 n + 1}] + n + 1}{1 + [x^{2}] + [x] + 2 x}

n ϵ N

Join BYJU'S Learning Program