Question

$\underset{x\to 0}{lim}\frac{{\left(1+x\right)}^n-1}{x}$ is

• A. $n$
• B. $1$
• C. $-n$
• D. $0$

Answer 1

Answer: (A)

$n$

using L hospital rule , diff numerator and denominator w.r.t x ,we get

$\frac{n(1+x{)}^{n-1}}{1}$

now putting limits $x\to 0$, we get

=n