Limx -4 f x - f -4x - -4 - where f x - sin 2x

Solution lim_x→π4sin 2x 1/x π/4 Apply L Hospital Rule lim_x→π4 #160; 2cosx = 2× 0 = 0 ...

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Limit

limx →π/4 f x...

Question

$lim x \to \frac{π}{4} \frac{f (x) - f (\frac{π}{4})}{x - \frac{π}{4}},$ where $f (x) = sin 2 x$

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${lim}_{x \to \frac{π}{4}} \frac{f (x) - f (\frac{π}{4})}{x - \frac{π}{4}}$ , where f(x) = sin 2x

lim x \to \frac{π}{4} \frac{f (x) - f (\frac{π}{4})}{x - \frac{π}{4}}

f (x) = sin 2 x

f (x) = 2 [x] + cos ([- π] x)

[.]

f (x) = 0

f (- π) = f (π) = 0

f (\frac{π}{2}) = - \frac{3 π^{2}}{4}

lim x \to - π \frac{f (x)}{sin (sin x)}

f (x) = \frac{1 - sin x}{sin 2 x}, x \neq \frac{π}{2}

f (x)

x = \frac{π}{2}

f (\frac{π}{2})

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