$F_{2}$ is a stronger oxidizing agent than ${C l}_{2}$ in aqueous solution. This is attributed to many factors except:

heat of dissociation

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electron affinity

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ionisation potential

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heat of hydration

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Solution

The correct option is B ionisation potential
In oxidizing process in aqueous solution these processes are involved.
$F_{2} \to 2 F R e^{-} - - \to 2 F^{-} (g) - ----- \to h y d r a t i o n 2 F^{-} (a q)$
Ionization potential is not involved.

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Similar questions

F_{2}

C l_{2}

{C r}^{2 +}

{F e}^{2 +}

Which is a better oxidizing agent cl2 or f2

F_{2}

{C l}_{2}

F_{2} < {C l}_{2} < {B r}_{2} < I_{2}

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