Question

$H_2{O}_2$ is sold as a solution of approximately $5.0g{H}_2{O}_2$ per $100ml$ of the solution the molecular mass of $H_2{O}_2$ is $34.$ The molarity of this solution is approximately:

• A. $1.15M$
• B. $1.5M$
• C. $3.0M$
• D. $3.4M$

Answer 1

The correct option is A $1.15M$

Molarity of compound $=\frac{Massofsolute}{Molarmass}\times \frac{1000}{V\left(inmL\right)}$

Here, Molarity of $H_2{O}_2=\frac{5}{34}\times \frac{1000}{100}=\frac{50}{34}=1.5$ $M$

Molarity of solution $=1.5$ $M$