If A-2I then n-N then An-

The correct option is B 2^n 1A → A=2I A^n=(2I)^n =2^n I^n =2^n I =2^n 1(2I) =2^n 1A ...

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Pascal Triangle

If A=2I the...

Question

$I f$ $A = 2 I$ then $n \in N$ then $A^{n} =$

2^{n - 1} A

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2^{n} A

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n A

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2 n

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Similar questions

If A = (\begin{matrix} 1 & 0 1 & 1 \end{matrix}] and I = (\begin{matrix} 1 & 0 0 & 1 \end{matrix}], then which of the following holds for all n \in N ?

A

A^{2} = 2 A - I

I

n \geq 2

A^{n}

Matrix A is such that $A^{2} = 2 A - I,$ where I is the Identity matrix. Then for $n \geq 2, A^{n}$ is equal to

A^{2}

(I + A)^{n}

a = \infty \sum n = 1 \frac{2 n}{(2 n - 1)!}, b = \infty \sum n = 1 \frac{2 n}{(2 n + 1)!}

a b

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