$N H_{3}$ on burning in oxygen gives :

N O a n d H_{2} O

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N O_{2}

and

H_{2} O

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N_{2} a n d H_{2} O

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N_{2} O a n d H_{2}

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Solution

The correct option is A $N O a n d H_{2} O$
$2 N H_{3} + \frac{5}{2} O_{2} \to 2 N O + 3 H_{2} O$

$4 N H_{3} + 5 O_{2} \to 4 N O + 6 H_{2} O$

NO and $H_{2} O$ are formed.

Option A is correct.

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