C- is a unit Vector orthogonal to a- b- where a- b- are a-k- b-2-2k- then c-

The correct option is C k̂ ĵ/√(2) c⃗=a⃗×b⃗|a⃗×b⃗| as (a⃗,b⃗,c⃗ are R.H.S) a⃗×b⃗=î amp; ĵ amp; k̂ 1 amp; 1 amp; 1 0 amp; ...

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Multiplication with Vectors

c⃗ is a unit ...

Question

$\to c$ is a unit Vector orthogonal to $\to a, \to b$ where $\to a, \to b,$ are $\to a =^i +^j +^k, \to b = 2^j + 2^k$ , then $\to c =$

\frac{^i +^j}{\sqrt{2}}

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\frac{^j +^k}{\sqrt{2}}

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\frac{^i -^k}{\sqrt{2}}

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\frac{^k -^j}{\sqrt{2}}

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\to a =^i +^j +^k

\to b =^i -^j +^k

\to c =^i +^j -^k

\to a =^i -^j -^k

(\to a \times \to b) \times (\to c \times \to d)

\to a =^i +^j +^k, \to b =^i +^j -^k

\to c =^i -^j +^k

\to d =^i -^j -^k

(\to a \times \to b) \times (\to c \times \to d) =

\to a =^i +^j -^k, \to b = -^i + 2^j + 2^k

\to c = -^i + 2^j -^k

\to a + \to b

\to b + \to c

\to a =^i +^j +^k, \to b =^i -^j +^k, \to c =^2 i +^3 j -^k

(\to a \times \to b) \times \to c =

\to a = 2^i +^j - 3^k, \to b =^i - 2^j +^k

\to c = -^i +^j - 4^k

\to d =^i +^j +^k

| (\to a \times \to b) \times (\to c \times \to d) |

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