You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Physics

Second Law of Motion

Maximum force...

Question

Maximum force exerted by the bat on the ball is:

2500 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5000 N

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

7500 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1250 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $5000 N$
Mass of balls
$\Rightarrow m_{b} = 250 g$
$u_{b_{1}} = 30 m / s$
abler strike $u_{b_{2}} = 50 m / s$
$\Rightarrow △ u = 20 m / s$
$\Rightarrow \frac{△ u}{t} = 20 \times 10^{3} m / s$
$\Rightarrow F = m \times \frac{△ u}{t} = 20 \times 10^{3} \times .250$
$= 5000 N$
Hence, the answer is $5000 N .$

Suggest Corrections

Similar questions

Q. A ball of mass 100 g is moving with a velocity of 10 m

s^{- 1}

. The force of the blow by the bat acts for 0.01 seconds. What is the force exerted on the ball by the bat if the ball retraces its path with same speed?

Q. A ball of mass

200 g

is thrown with a speed

20 m s^{- 1}

. The ball strikes a bat and rebounds along the same line at a speed

40 m s^{- 1}

Variation of the interaction force, as long as the ball remains in contact with the bat, is as shown in Fig. Average force exerted by the bat on the ball is:

Q. A cricket ball of mass

150 g

is moving with a velocity of

12 m / s

and is hit by a bat so that the ball is turned back with a velocity of

20 m / s

. The force of blow acts for

0.01 s

on the ball. The average force exerted by the bat on the ball is (in

N

)

A cricket ball of mass 150 gm is moving with a velocity of 12 m/s and is hit by a bat so that the ball is turned back with a velocity of 20 m/s. The force of blow acts for 0.01s on the ball. The average force exerted by the bat on the ball is

Q. A cricket ball weighing

100 g

and moving with a speed of

20 {m s}^{- 1}

strikes a bat and remains is contact with it for

0.1 s

. The average force exerted by the ball on the bat is:

Join BYJU'S Learning Program

Maximum force exerted by the bat on the ball is:

The correct option is B 5000NMass of balls⇒mb=250g ub1=30m/sabler strike ub2=50m/s⇒△u=20m/s⇒△ut=20×103m/s⇒F=m×△ut=20×103×.250 =5000NHence, the answer is 5000N.