Maximum number of electrons in an atom that can have the quantum numbers $n = 4, m_{e} = + 1$ is:

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Solution

The correct option is C 6
We know for a given $n$ , the value of $m_{e} = + l t o - l$ and $l = 0 t o (n - 1)$ .

For $n = 4$
$l = 0 m_{e} = 0$
$l = 1 m_{e} = - 1, 0, + 1$ ;
$l = 2 m_{e} - 2, - 1, 0, + 1, + 2$ $l = 3 m_{e} = - 3, - 2, - 1, 0, + 1, + 2, + 3$
There are three orbitals having $m_{e} = + 1$ . Thus maximum number of electrons in them will be $3 \times 2 = 6.$

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