Maximum $p K_{b}$ value is of :

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(C H_{3} C H_{2})_{2} N H

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(C H_{3})_{2} N H

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Solution

The correct option is D
Greater the value of $p K_{b}$ , smaller is the $K_{b}$ and hence weaker is the base. Basicity of amines can be attributed to their ease of donation of lone pair.
From the given option, diphenylamine (d) is the least basic since lone pair of electron is delocalising over two phenyl ring and hence is least available for donation.

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