Maximum voltage produced in an AC generator completing 60 cycles in 30 second is 250 V. What is the period of the armature?

0.5 s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

30 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 0.5 s
Given: Time (t) = 30 seconds, Rotations = 60
Period = Time taken to complete one full rotation.

Period = $\frac{Time taken for rotation}{Number of rotations} = \frac{30}{60}$
= $\frac{1}{2}$ = 0.5 s

Suggest Corrections

Similar questions

E = 170 sin 377 t

t

E = 240 sin 120 t

t

V = 5 s i n (100 π t - \frac{π}{6})

I = 4 s i n (100 π t + \frac{π}{6})

Join BYJU'S Learning Program