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Question

Mean deviation of 39,40,40,41,41,42,42,43,43,44,44,45 from their median is?

A
15
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B
1.5
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C
42
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D
35
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Solution

The correct option is B 1.5
Arranged data is
39,40,40,41,41,42,42,43,43,44,44,45
Since N=12=even
Median=(N/2)+[(N/2)+1]2th term
Median=42+422=42=M (Let)
Now, Mean deviation =|xiM|N
=3+2+2+1+1+1+0+0+1+1+2+2+312=1.5

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