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Standard XII

Physics

Introduction

Mean kinetic ...

Question

Mean kinetic energy (or average) per gm.molecule of a monoatomic gas is given by:

\frac{3 R T}{2}

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\frac{k T}{2}

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\frac{R T}{3}

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\frac{3 k T}{2}

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Solution

The correct option is A $\frac{3 R T}{2}$
Mean kinetic energy for a molecule is given as $E = \frac{3}{2} k T$
For calculating the energy of one mole just multiply it by $N_{a}$ where $N_{a}$ is Avogadro's number so
required energy is $N_{a} (3 k T / 2) = \frac{3 R T}{2}$
Option A is correct.

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Similar questions

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, where,

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Translational kinetic energy of n mole \frac{1}{2} M u^{2} = \frac{3}{2} (P V) = \frac{3}{2} (n R T)

Average translational kinetic energy per molecule = \frac{3}{2} (\frac{R T}{N_{A}}) = \frac{3}{2} (K T)

u_{r m s} = \sqrt{\frac{3 P V}{M}} = \sqrt{\frac{3 R T}{M}} = \sqrt{\frac{3 P}{d}}

and

u_{a v} = \sqrt{\frac{8 R T}{π M}}

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Mean kinetic energy (or average) per gm.molecule of a monoatomic gas is given by:

The correct option is A 3RT2Mean kinetic energy for a molecule is given as E=32kTFor calculating the energy of one mole just multiply it by Na where Na is Avogadro's number so required energy is Na(3kT/2)=3RT2Option A is correct.

The correct option is A $\frac{3 R T}{2}$
Mean kinetic energy for a molecule is given as $E = \frac{3}{2} k T$
For calculating the energy of one mole just multiply it by $N_{a}$ where $N_{a}$ is Avogadro's number so
required energy is $N_{a} (3 k T / 2) = \frac{3 R T}{2}$
Option A is correct.