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Byju's Answer
Standard XII
Chemistry
Classification of Hydrocarbons
MeCH=CH-CH=C=...
Question
M
e
C
H
=
C
H
−
C
H
=
C
=
C
H
−
C
H
=
C
H
2
Total number of geometrical isomers possible for above compund.
A
16
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B
8
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C
4
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D
2
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Solution
The correct option is
C
4
M
e
C
H
=
C
H
−
C
H
=
C
=
C
H
−
C
H
=
C
H
2
1 2
As the given compound is asymmetric, so the total number of geometrical isomers=
2
n
=
2
2
=
4
[
∵
n
=
2
]
There are only 2 sites where geometrical isomerism is possible so n=2.
Therefore, the total number of geometrical isomers is=4
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