Question

Meena, Beena, and Reena are climbing the steps to the hilltop. Meena is at step $\mathrm{s}$, Beena is $8$ steps ahead, and Reena is $7$ steps behind. Where are Beena and Reena? The total number of steps to the hilltop is $10$ less than $4$ times what Meena has reached. Express the total number of steps using $\mathrm{s}$.

Answer 1

Given, that Meena is at step $\mathrm{s}$.

Finding Beena's step:

Since Beena is $8$ steps ahead of Meena,

Then the step at which Beena $=(\mathrm{step}\mathrm{at}\mathrm{which}\mathrm{Meena}\mathrm{is})+8$

$=(\mathrm{s}+8)$

Finding Reena's step:

Since Reena is $7$ steps behind Meena,

Then the step at which Reena $=(\mathrm{step}\mathrm{at}\mathrm{which}\mathrm{Meena}\mathrm{is})-7$

$=(\mathrm{s}-7)$

Finding the total number of steps:

According to the question,

Total number of steps $=4(\mathrm{step}\mathrm{at}\mathrm{which}\mathrm{Meena}\mathrm{is})-10$

$=4\mathrm{s}-10$

Therefore, Beena is at step $(\mathrm{s}+8)$, Reena is at step $(\mathrm{s}-7)$, and the total number of steps is $(4\mathrm{s}-10)$.