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Quantitative Aptitude

Dependent Events

Meghana and B...

Question

Meghana and Bobbby are among the 5 participants in a cycling race. If each participant finishes the race and no two participants finish at the same time, in how many different possible orders can the participants finish the race so that Meghana finishes ahead of Bobbby?

A

24

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B

30

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C

60

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D

90

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Solution

The correct option is C 60
Fastest way is $\frac{5!}{2} = 60$ . Since in all possible combinations, half of the time Meghana will be ahead of Bobbby, the other half Bobbby will be ahead of Meghana. So we divide all possible outcomes by two

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