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Question
Melting point of three substances a, b, c are 52 degree Celsius and 75 degree Celsius and 80 degree Celsius. Arrange them in the decreasing order of the interparticle force of attraction in each of them. Also ive a reason for the answer.
Melting point of three substances a, b, c are 52 degree Celsius and 75 degree Celsius and 80 degree Celsius. Arrange them in the decreasing order of the interparticle force of attraction in each of them. Also ive a reason for the answer.
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Solution
Melting point is directly proportional to the strength of bond as, stronger the bond higher will be the melting point.
So, the matter with minimum melting point i.e. 52°For A will have the minimum intermolecular or inter particular force of attraction so that the bond will be weakest.
The most stronger intermolecular force will be found in C with 80℃ melting point .Also B with 75℃ will have strong inter molecular force compared to A.
So the decreasing order of intermolecular force would be , C>B>A
Melting point is directly proportional to the strength of bond as, stronger the bond higher will be the melting point.
So, the matter with minimum melting point i.e. 52°For A will have the minimum intermolecular or inter particular force of attraction so that the bond will be weakest.
The most stronger intermolecular force will be found in C with 80℃ melting point .Also B with 75℃ will have strong inter molecular force compared to A.
So the decreasing order of intermolecular force would be , C>B>A
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