Mercury (II) chloride reacts with aqueous ammonia to give

H g_{2} (N H_{2})_{2}

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H g (N H_{2})_{2}

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H g (N H_{2}) C l

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N H_{4} C l

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Solution

The correct options are
B $H g (N H_{2}) C l$
D $N H_{4} C l$
When Mercury (II) chloride reacts with aqueous ammonia the following reaction takes place:

$H g C l_{2} + 2 N H_{3} a q . \to H g (N H_{2}) C l + N H_{4} C l M e r c u r y a m i n o c h l o r d e$

In this reaction, $H g (N H_{2}) C l$ and $N H_{4} C l$ is formed.

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Similar questions

H g_{2} C l_{2}

H g N H_{2} C l

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