Question

Mercury is poured in a $U-$ tube. Temperature of one side is ${50}^{O}C$ and the level of mercury on this side is $h_1$. Temperature of the outer side is ${100}^{O}C$ and the level of mercury on this side is $h_2$. Then

• A. $h_1=h_2$
• B. $h_2>h_3$
• C. $h_2>h_1$
• D. $h_2=2h_1$

Answer 1

Answer: (C)

$h_2>h_1$

We know mercury is a metal and it expands on heating.

As the temperature of the outer side is 100 degrees which is higher than the inner side , $h_2$ will be greater than $h_1$

The expansion is given by: $\Delta l=l_o(1+\Delta T)$