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Question

Metal oxides are formed during the reaction between a metal cation and oxygen gas. Since transition metals can have two or more valence shell configurations, there can be more than one metal oxide formula for a given transition metal. Based on this knowledge, what is the correct empirical formula for chromium (IV) oxide?

A
Cr2O
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B
CrO2
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C
Cr2O4
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D
Cr4O2
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Solution

The correct option is D CrO2
In Chromium (IV) Oxide, the Oxidation state of Cr is 4+. Oxygen is present here O2
So, Cr O
4 2
=CrO2
So, the correct formula is CrO2
Option B is the correct empirical formula of Chromium (IV) Oxide.

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