The work function (ϕ) of some metals is listed below. The number of metals which will show photoelectric effect when light of 300nm wavelength falls on the metal is:
A
4
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B
3
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C
5
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D
2
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Solution
The correct option is A4 The energy associated with incident photon =hcλ E=6.6×10−34×3×108300×10−9J E in ev6.6×10−34×3×108300×10−9×1.6×10−19=4.16ev
Now Li,Na,K,Mg have work function less than 4.14 eV