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Question

Mg2C3 [X] is decomposed by H2O forming a gaseous hydrocarbon [Y]. 8.4 g of [X] gives _________ mol of [Y].

A
0.1
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B
0.2
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C
0.3
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D
0.4
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Solution

The correct option is A 0.1
Solution:- (A) 0.1
As we know that,
No. of moles=Given weightMol. weight
Weight of Mg2C3=8.4g
Molecular weight of Mg2C3=84g
Therefore,
No. of moles =8.484=0.1 mol
Decomposition of Mg2C3 by H2O-
Mg2C3[X]+4H2O2Mg(OH)2+C3H4[Y]
From the above reaction,
1 mole of Mg2C3 gives 1 mole of [Y].
Therefore,
0.1 mole of Mg2C3 gives 0.1 mole of [Y].
Hence 8.4g of X gives 0.1 mole of Y.

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