Question

$M{g}_3{B}_2\stackrel{HC{l}_{\left(aq\right)}}{\to }\left[X\right]+MgC{l}_2.$

For [X] and [Y], the incorrect choice is :

• A. $\left[X\right]+H_{2}O\stackrel{HC{l}_{\left(aq\right)}}{\to }\left[Y\right]+H_2$
• B. [X] is $BC{l}_3$ and [Y] is $H_{3}B{O}_3$
• C. [X] with air and [Y] on strong heating (red heat) give same compound
• D. In [Y], Boron completes its octet by removing $H^{+}$ from water molecule

Answer 1

The correct option is B [X] is $BC{l}_3$ and [Y] is $H_{3}B{O}_3$

$2M{g}_3{B}_2+12HC{l}_{(aq.)}\to 2B_2{H}_6+6MgC{l}_2$

$\left(X\right)$

$B_2{H}_6+3H_{2}O\to H_{3}B{O}_3+3H_2$

$\left(X\right)$ $\left(Y\right)$

$B_2{H}_6+3O_2\stackrel{\Delta }{\to }{B}_2{O}_3+3H_{2}O$

$2H_{3}B{O}_3\stackrel{\Delta }{\to }{B}_2{O}_3+3H_{2}O$

$\left(Y\right)$

$H_{3}B{O}_3+H_{2}O\leftrightharpoons H^{+}+\left[B\right(OH{)}_4{]}^{-}$

In Y, B completes it octet by removing $H^{+}$ from water molecule.