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Byju's Answer
Standard XII
Chemistry
Nernst Equation
Mg in the sol...
Question
Mg in the solid state
(
M
g
(
s
)
)
+
2
A
g
+
(
0.001
M
)
→
M
g
2
+
(
0.130
M
)
+
2
A
g
(
s
)
represent the cell. Calculate the emf of the cell at
298
K.
Given:
E
o
c
e
l
l
=
3.17
V.
Open in App
Solution
M
g
(
s
)
+
2
A
g
+
(
0.001
M
)
→
M
g
+
2
(
0.130
M
)
+
2
A
g
(
s
)
T
=
298
K
n
=
2
E
o
c
e
l
l
=
3.17
E
m
f
=
E
o
c
e
l
l
−
0.0591
n
l
o
g
[
P
]
[
R
]
E
m
f
=
3.17
−
0.0591
2
l
o
g
0.130
0.001
=
3.17
−
0.0591
2
(
2.11
)
=
3.17
−
(
0.0295
)
×
2.11
=
3.17
−
0.0622
=
3.1078
V
The EMF of the cell is
3.10
V
Suggest Corrections
0
Similar questions
Q.
Represent the cell in which the following reaction takes place
M
g
(
s
)
+
2
A
g
+
(
0.0001
M
)
→
M
g
2
+
(
0.130
M
)
+
2
A
g
(
s
)
Calculate its
E
(
c
e
l
l
)
if
E
o
(
c
e
l
l
)
=
3.17
V
Q.
The following reactions occurs in the cell
M
g
(
s
)
+
2
A
g
+
(
0.0001
M
)
⇌
M
g
2
+
(
0.130
M
)
+
2
A
g
(
s
)
. Calculate
E
(
c
e
l
l
)
E
0
(
c
e
l
l
)
=
3.17
v
o
l
t
Q.
Answer the following questions:
a) Calculate the EMF of the cell for the reaction
M
g
(
s
)
+
2
A
g
+
(
a
q
)
→
M
g
2
+
(
a
q
)
+
2
A
g
(
s
)
.
Given :
E
0
M
g
2
+
/
M
g
=
−
2.37
V
E
0
A
g
+
/
A
g
=
0.80
V
[
M
g
2
+
]
=
0.001
M
;
[
A
g
+
]
=
0.0001
M
b) What are fuel cells?
Q.
For the cell reaction,
M
g
(
s
)
+
2
A
g
+
(
a
q
.
)
⇌
M
g
2
+
(
a
q
.
)
+
2
A
g
(
s
)
E
∘
c
e
l
l
is
+
3.17
V
at
298
K
. The value of
E
c
e
l
l
,
△
G
∘
and
Q
at
A
g
+
and
M
g
2
+
concentrations of
0.001
M
and
0.02
M
respectively are:
Q.
For the cell reaction at
25
∘
C
,
M
g
(
s
)
+
2
A
g
+
(
a
q
)
⇌
M
g
2
+
(
a
q
)
+
2
A
g
(
s
)
E
0
c
e
l
l
=
+
3.17
V
The values of
E
c
e
l
l
,
Δ
G
0
and
Q
respectively , at
[
A
g
+
]
=
10
−
3
M
and
[
M
g
2
+
]
=
0.02
M
are:
Here,
Q
is reaction quotient
l
o
g
2
=
0.301
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