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Question

Middle term in the expansion of (1+3x+3x2+x3)6 is


A

4th

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B

3rd

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C

10th

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D

None of these

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Solution

The correct option is C

10th


(1+3x+3x2+x3)6 = ((1+x)3)6 = (1+x)18

Hence the middle term is 10th.


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