milli moles of the solute are present in 350mL solution which is 0.75M.
A
26.25
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B
2.625
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C
0.2625
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D
262.5
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Solution
The correct option is D 262.5 We know that,
Molarity = MolesofsoluteVolumeinlitresofsolution
Number of milli-moles=Molarity×[volumeofsolutioninml] =0.75×350 =262.5