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Question

milli moles of the solute are present in 350 mL solution which is 0.75 M.

A
26.25
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B
2.625
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C
0.2625
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D
262.5
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Solution

The correct option is D 262.5
We know that,
Molarity = Moles of soluteVolume in litres of solution
Number of milli-moles=Molarity×[volume of solution in ml]
=0.75×350
=262.5

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