Mimas is one of Saturn's many moons.. The orbital distance of Mimas, from Saturn is 1.87 $\times$ $10^{8}$ m. Its mean orbital period is approximately 23 hours. Calculate the speed with which it revolves around Saturn.

21,274 m/s

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7,091 m/s

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28,366 m/s

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14,183 m/s

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Solution

The correct option is D
14,183 m/s

Speed = $\frac{C i r c u m f e r e n c e o f t r a j e c t o r y}{T i m e p e r i o d}$

= $\frac{2 π R}{T}$

= $\frac{2 \times 3.14 \times 1.87 \times 10^{8}}{23 \times 3600}$ $\frac{m}{s}$

= 14183 $\frac{m}{s}$

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Q. One of Saturn's moon is named as Mimas. The orbital distance of Mimas is

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One of Saturn's moon is named as Mimas. The orbital radius of Mimas is 1.87 $\times$ $10^{8}$ m. The time taken to complete one revolution by Mimas around Saturn is approximately 23 hours. The speed of Mimas with which it revolves around Saturn is

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Mimas is one of Saturn's many moons.. The orbital distance of Mimas, from Saturn is 1.87 × 108 m. Its mean orbital period is approximately 23 hours. Calculate the speed with which it revolves around Saturn.

The correct option is D 14,183 m/s Speed = Circumference of trajectoryTime period = 2πRT = 2×3.14×1.87×10823×3600 ms = 14183 ms

Mimas is one of Saturn's many moons.. The orbital distance of Mimas, from Saturn is 1.87 $\times$ $10^{8}$ m. Its mean orbital period is approximately 23 hours. Calculate the speed with which it revolves around Saturn.

The correct option is D
14,183 m/s

Speed = $\frac{C i r c u m f e r e n c e o f t r a j e c t o r y}{T i m e p e r i o d}$

= $\frac{2 π R}{T}$

= $\frac{2 \times 3.14 \times 1.87 \times 10^{8}}{23 \times 3600}$ $\frac{m}{s}$

= 14183 $\frac{m}{s}$