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Question

Minimise Z=x+2y
subject to 2x+y3,x+2y6,x,y0

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Solution

The feasible region determined by the constraints, 2x+y3,x+2y6,x0,y0 is as shown.
The corner points of the feasible region are A(6,0) and B(0,3)
The values of Z at these corner points are as follows.
Corner point Z=x+2y
A(6,0)6
B(0,3)6
It can be seen that the value of Z at points A and B is same. If we take any other point such as (2,2) on line x+2y=6, then Z=6
Thus, the minimum value of Z occurs for more than 2 points, and is equal to 6
386363_422936_ans.PNG

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