MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Froth Floatation

minimum

Question

minimum % labelling of oleum

Open in App

Solution

Suggest Corrections

thumbs-up

4

Similar questions

100

109 %

labelling present in a container. Which is/are correct statements?

Q. An oleum sample is labelled as

118 %

H_{2} S O_{4}

100

g oleum sample is:

Q. The percent free

S O_{3}

20 %

. Label the sample of oleum in terms of percent

H_{2} S O_{4}

.

Q. Oleum is considered as a solution of

S O_{3}

H_{2} S O_{4}

, which is obtained by passing

S O_{3}

H_{2} S O_{4}

. When 100 g sample of oleum is diluted with desired mass of

H_{2} O

then the total mass of

H_{2} S O_{4}

obtained after dilution is known as % labelling in oleum.
For example, a oleum bottle labelled as '109 %

H_{2} S O_{4}

' means the 109 g total mass of pure

H_{2} S O_{4}

will be formed when 100 g of oleum is diluted by 9 g of

H_{2} O

which combines with all the free

S O_{3}

present in oleum to form

H_{2} S O_{4}

S O_{3} + H_{2} O \to H_{2} S O_{4}

.

What is the % of free

S O_{3}

in an oleum that is labelled as '104.5 %

H_{2} S O_{4}

Q. A mixture is prepared by mixing

10 g H_{2} S O_{4}

40 g S O_{3}

. FInd the % labeling of oleum.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Froth Floatation

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Froth Floatation

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon