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Redox Reactions and Couple

Mn 2+ can be ...

Question

${M n}^{2 +}$ can be converted into ${M n}^{2 +}$ by reacting with

P b O_{2}

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S n {C l}_{2}

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{S O}_{2}

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{C l}_{2}

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Solution

The correct option is A $P b O_{2}$
Strong, oxidising agens such as $P b O_{2}$ or sodium bismuthate $(N a B i O_{3})$ oxidise ${M n}^{2 +}$ to $M n O_{4}^{-}$ or ${M n}^{7 +}$

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Similar questions

{M n}^{2 +}

{M n}^{7 +}

{M n}^{2 +} + P b O_{2} ⟶ M n O_{4}^{-} + H_{2} O

{M n}^{2 +}

M n O_{4}^{-}

S O_{2}

M n O_{4}^{-}

M n^{2 +}

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M n^{2 +} (a q)

{M n O_{4}}^{-} (a q)

M n^{2 +} + {M n O_{4}}^{-} + {O H}^{-} \to M n O_{2} + H_{2} O (unbalanced)

25.0

M n^{2 +}

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0.05876 M K M n O_{4}

M n^{2 +}

y \times 10^{- 4} M

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