$M n O_{2} + 4 H C l \to M n {C l}_{2} + 2 H_{2} O + {C l}_{2}$
In the above equation, name the compound which is oxidized and the compound which is reduced?

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Solution

$H C l$ is oxidised to $C l_{2}$ where as $M n O_{2}$ is reduced to $M n^{+ 2}$ in $M n C l_{2} .$

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Q. In the reaction

\to

M N O_{2} + 4 H C L \to M n C l_{2} + 2 H_{2} O + C l_{2}

(a) name the compound (i) oxidised (ii) reduced
(b) define oxidation of reduction on its basis.

Q. Identify the substance oxidized,substance reduced ,oxidizing agent and reducing agent :

M n O_{2} + 4 H C L \to M n C l_{2} + 2 H_{2} O + C l_{2}

Identify the substance oxidized, substance reduced, oxidising agent and reducing agent.
$M n O_{2}$ + $4 H C l$ $\to$ $M n {C l}_{2}$ + $2 H_{2} O$ + ${C l}_{2}$ .

Q. Which substance/ion is oxidised and which substance/ion is reduced in the following reaction?

M n O_{2} + 4 H C l \to M n C l_{2} + 2 H_{2} O + C l_{2}

4 H C l + M n O_{2} \to M n C l_{2} + 2 H_{2} O + C l_{2}

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MnO2+4HCl→MnCl2+2H2O+Cl2In the above equation, name the compound which is oxidized and the compound which is reduced?

HCl is oxidised to Cl2 where as MnO2 is reduced to Mn+2 in MnCl2.

$M n O_{2} + 4 H C l \to M n {C l}_{2} + 2 H_{2} O + {C l}_{2}$
In the above equation, name the compound which is oxidized and the compound which is reduced?

$H C l$ is oxidised to $C l_{2}$ where as $M n O_{2}$ is reduced to $M n^{+ 2}$ in $M n C l_{2} .$