Mn O 2 -HCl - A g A g - F 2 excess 573K B g B l - U s - C g - D g The gases A- B- C and D are respectively -

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Ideal Gas Equation

Mn O 2 +HCl ...

Question

$M n O_{2} + H C l Δ - ------- \to A_{(g)}$
$A_{(g)} + F_{2 (e x c e s s)} 573 K - ------ \to B_{(g)}$
$B_{(l)} + U_{(s)} ⟶ C_{(g)} + D_{(g)}$
The gases $A$ , $B$ , $C$ and $D$ are respectively :

{C l}_{2}, C l F_{3}, U F_{6}, C l F

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O_{2}, O_{2} F_{2}, U_{2} O_{3}, O F_{2}

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{C l}_{2}, C l F, U F_{6}, C l F_{3}

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O_{2}, O F_{2}, U_{2} O_{3}, O_{2} F_{2}

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O

O_{2}, O_{3}, O F_{2}

B a O_{2}

F_{2}

C l F

{C l F}_{3}

The reaction ; $2 O_{3}$ → $3 O_{2}$ , is assigned the following mechanism.

(I) $O_{3} ⇋ O_{2} + O (i i) O_{3} + O s l o w ⇌ 2 O_{2}$

The rate law of the reaction will therefore be

O_{3} \Leftrightarrow O_{2} + O (f a s t) O + O_{3} \to 2 O_{2} (s l o w)

O - O

O_{2}, H_{2} O_{2}, O_{3}

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